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0.015x^2-2x^2+70x=500
We move all terms to the left:
0.015x^2-2x^2+70x-(500)=0
We add all the numbers together, and all the variables
-1.985x^2+70x-500=0
a = -1.985; b = 70; c = -500;
Δ = b2-4ac
Δ = 702-4·(-1.985)·(-500)
Δ = 930
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-\sqrt{930}}{2*-1.985}=\frac{-70-\sqrt{930}}{-3.97} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+\sqrt{930}}{2*-1.985}=\frac{-70+\sqrt{930}}{-3.97} $
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